Question

Datetime Variable Creation

0

Hi All, I have a scenario that need to create a date time variable with fixed month and day (31/12) and the year is stored in another int variable, Any one has any idea? Datetime function couldn’t be used since i have the year value in a variable. Any ideas?

asked 2020-07-13

Aseel Huneidi

2 answers

Rom van Arendonk · Answer 1 · 2020-07-13

You could try something like: addYearsUTC(dateTimeUTC(2000, 12, 31, 0, 0, 0), $Year-2000)

Edwin van Elk · Answer 2 · 2020-07-13

Or something like:

parseDateTime(toString($Jaar) + '-12-31', 'yyyy-MM-dd') ?